What is the answer to log_{4}(2x-7)=3 ?

The answer to log_{4}(2x-7)=3 is x= 71/2

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log_{4}(2x-7)=3

lo g_{4} (2 x - 7) = 3

x = \frac{71}{2}

Decimal

x = 35.5

Solution steps

lo g_{4} (2 x - 7) = 3

Apply log rules

2 x - 7 = 64

Solve

2 x - 7 = 64 : x = \frac{71}{2}

x = \frac{71}{2}

ln (x + a^{2} + x^{2})

ln (x) - ln (x^{2}) = \frac{1}{2}

lo g_{10} (2 x) + lo g_{10} (x) = lo g_{10} (5) + 1

ln (x) + ln (x + 1) = 4

lo g_{\frac{1}{6}} (3 - 10 x) = - 2

What is the answer to log_{4}(2x-7)=3 ?
The answer to log_{4}(2x-7)=3 is x= 71/2
Solve for x: log_{4}(2x-7)=3
The solution is x= 71/2