What is the answer to ln(x)+ln(4x)=2 ?

The answer to ln(x)+ln(4x)=2 is x=e^{(2-2ln(2))/2}

Solve for x: ln(x)+ln(4x)=2

The solution is x=e^{(2-2ln(2))/2}

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ln (x) + ln (4 x) = 2

x = e^{\frac{2 - 2 l n ( 2 )}{2}}

Decimal

x = 1.35914 \dots

Solution steps

ln (x) + ln (4 x) = 2

Apply log rules

x = e^{\frac{2 - 2 l n ( 2 )}{2}}

Verify Solutions:

x = e^{\frac{2 - 2 l n ( 2 )}{2}}

True

The solution is

x = e^{\frac{2 - 2 l n ( 2 )}{2}}

0.25 = - 0.25 lo g_{e} (1 - c)

lo g_{4} (2 x - 5) = 4

26 = 10 lo g_{10} (\frac{I}{1 0 ^{- 16}})

lo g_{10} (x + 9) = lo g_{10} (x) + lo g_{10} (9)

lo g_{10} (2 x - 1) = 10

What is the answer to ln(x)+ln(4x)=2 ?
The answer to ln(x)+ln(4x)=2 is x=e^{(2-2ln(2))/2}
Solve for x: ln(x)+ln(4x)=2
The solution is x=e^{(2-2ln(2))/2}