What is the answer to log_{10}(7x+15)-log_{10}(5)=1 ?

The answer to log_{10}(7x+15)-log_{10}(5)=1 is x=5

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log_{10}(7x+15)-log_{10}(5)=1

lo g_{10} (7 x + 15) - lo g_{10} (5) = 1

x = 5

Solution steps

lo g_{10} (7 x + 15) - lo g_{10} (5) = 1

Move

lo g_{10} (5)

to the right side

lo g_{10} (7 x + 15) = 1 + lo g_{10} (5)

Apply log rules

7 x + 15 = 50

Solve

7 x + 15 = 50 : x = 5

x = 5

Verify Solutions:

x = 5

True

The solution is

x = 5

lo g_{2} (3 x + 6) = 5

lo g_{b} (27) = - 0.5

lo g_{10} (x) - lo g_{10} (3) = 1

lo g_{7} (x^{2} + 3 x) = 2

lo g_{x + 1} (x^{2} + 3) = 2

What is the answer to log_{10}(7x+15)-log_{10}(5)=1 ?
The answer to log_{10}(7x+15)-log_{10}(5)=1 is x=5
Solve for x: log_{10}(7x+15)-log_{10}(5)=1
The solution is x=5