What is the answer to x=9-ln(2x) ?

The answer to x=9-ln(2x) is x=\W_{0}((e^9)/2)

Solve for x: x=9-ln(2x)

The solution is x=\W_{0}((e^9)/2)

Popular >

x = 9 - ln (2 x)

x = W_{0} (\frac{e ^{9}}{2})

Decimal

x = 6.44374 \dots

Solution steps

x = 9 - ln (2 x)

Move

ln (2 x)

to the left side

x + ln (2 x) = 9

Move

x

to the right side

ln (2 x) = 9 - x

f (x) = g (x),

then

a^{f (x)} = a^{g (x)}

e^{l n (2 x)} = e^{9 - x}

Simplify

e^{l n (2 x)} : 2 x

2 x = e^{9 - x}

Solve

2 x = e^{9 - x} : x = W_{0} (\frac{e ^{9}}{2})

x = W_{0} (\frac{e ^{9}}{2})

Verify Solutions:

x = W_{0} (\frac{e ^{9}}{2})

True

The solution is

x = W_{0} (\frac{e ^{9}}{2})

lo g_{- 2 x - 3} (2 x^{2} - 2 x - 15) = 2

x, lo g_{3} (x) = 3

lo g_{10} (x) + lo g_{10} (x + 5) = 2

u, lo g_{u} (\frac{15}{16}) = v

lo g_{2} (6 \cdot 2^{2 n + 1} - 6) = n

What is the answer to x=9-ln(2x) ?
The answer to x=9-ln(2x) is x=\W_{0}((e^9)/2)
Solve for x: x=9-ln(2x)
The solution is x=\W_{0}((e^9)/2)