What is the answer to 2log_{10}(3-x)=-1 ?

The answer to 2log_{10}(3-x)=-1 is x=(-1+3sqrt(10))/(sqrt(10))

Solve for x: 2log_{10}(3-x)=-1

The solution is x=(-1+3sqrt(10))/(sqrt(10))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2 lo g_{10} (3 - x) = - 1

x = \frac{- 1 + 3 10}{10}

Decimal

x = 2.68377 \dots

Solution steps

2 lo g_{10} (3 - x) = - 1

Divide both sides by

2

lo g_{10} (3 - x) = - \frac{1}{2}

Apply log rules

3 - x = \frac{1}{10}

Solve

3 - x = \frac{1}{10} : x = \frac{- 1 + 3 10}{10}

x = \frac{- 1 + 3 10}{10}

Verify Solutions:

x = \frac{- 1 + 3 10}{10}

True

The solution is

x = \frac{- 1 + 3 10}{10}

lo g_{10} (x) 49 = 2

lo g_{10} (x^{2} + 4 x + 17) = 2

9 lo g_{4} (10 x + 4) = 27

lo g_{5} (- 8 x - 3) = 1

lo g_{10} (x^{2}) = 6

What is the answer to 2log_{10}(3-x)=-1 ?
The answer to 2log_{10}(3-x)=-1 is x=(-1+3sqrt(10))/(sqrt(10))
Solve for x: 2log_{10}(3-x)=-1
The solution is x=(-1+3sqrt(10))/(sqrt(10))