What are the solutions to the equation factor 2x^2-7x-9=0 ?

The solutions to the equation factor 2x^2-7x-9=0 are x=-1,x= 9/2

Find the zeros of factor 2x^2-7x-9=0

The zeros of factor 2x^2-7x-9=0 are x=-1,x= 9/2

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2 x^{2} - 7 x - 9 = 0

x = - 1, x = \frac{9}{2}

Solution steps

2 x^{2} - 7 x - 9 = 0

Factor

2 x^{2} - 7 x - 9 : (x + 1) (2 x - 9)

(x + 1) (2 x - 9) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 1 = 0 or 2 x - 9 = 0

Solve

x + 1 = 0 : x = - 1

Solve

2 x - 9 = 0 : x = \frac{9}{2}

The solutions to the quadratic equation are:

x = - 1, x = \frac{9}{2}

x^{2} - 4 = 5

14 x^{2} - 10 x^{2} = 0

x, ∣ x - 3 ∣ = 6

x^{2} - 12 x + 35 = 0

(2 p^{2} + 7 q) (2 p^{2} - 7 q)

What are the solutions to the equation factor 2x^2-7x-9=0 ?
The solutions to the equation factor 2x^2-7x-9=0 are x=-1,x= 9/2
Find the zeros of factor 2x^2-7x-9=0
The zeros of factor 2x^2-7x-9=0 are x=-1,x= 9/2