What is factor x^3-9 ?

The solution to factor x^3-9 is (x-\sqrt[3]{9})(x^2+\sqrt[3]{9}x+\sqrt[3]{9^2})

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Factor x^3-9

factor completely

x^{3} - 9

(x - 39) (x^{2} + 39 x + 3 9^{2})

Solution steps

x^{3} - 9

Apply radical rule:

a = (a)^{2}

9 = (39)^{3}

= x^{3} - (39)^{3}

Apply Difference of Cubes Formula:

x^{3} - y^{3} = (x - y) (x^{2} + x y + y^{2})

x^{3} - (39)^{3} = (x - 39) (x^{2} + 39 x + (39)^{2})

= (x - 39) (x^{2} + 39 x + (39)^{2})

(39)^{2} = 9^{\frac{2}{3}}

= (x - 39) (x^{2} + 39 x + 9^{\frac{2}{3}})

9^{\frac{2}{3}} = 3 9^{2}

= (x - 39) (x^{2} + 39 x + 3 9^{2})

A, b 2 A = \frac{1}{2} h (b_{1} + b_{2})

x, e^{l n (x^{2})} - 16 = 0

r, V = \frac{1}{3 p i r ^{2} h}

t, - lo g_{10} (12) = - (\frac{( lo g _{10} ( 2 ) )}{5.1}) t

\frac{( - 75 )}{( - 72 )}

What is factor x^3-9 ?
The solution to factor x^3-9 is (x-\sqrt[3]{9})(x^2+\sqrt[3]{9}x+\sqrt[3]{9^2})