What is the answer to solvefor A,b2A= 1/2 h(b_{1}+b_{2}) ?

The answer to solvefor A,b2A= 1/2 h(b_{1}+b_{2}) is A=(h(b_{1}+b_{2}))/(2b^2);\quad b\ne 0

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Solve for b2 A=1/2h(b_1+b_2)

solve for

A, b^{2} A = \frac{1}{2} h (b_{1} + b_{2})

A = \frac{h ( b _{1} + b _{2} )}{2 b ^{2}}; b \neq = 0

Solution steps

b^{2} A = \frac{1}{2} h (b_{1} + b_{2})

Divide both sides by

b^{2}; b \neq = 0

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What is the answer to solvefor A,b2A= 1/2 h(b_{1}+b_{2}) ?
The answer to solvefor A,b2A= 1/2 h(b_{1}+b_{2}) is A=(h(b_{1}+b_{2}))/(2b^2);\quad b\ne 0