What is factor 2x^2-19x+35 ?

The solution to factor 2x^2-19x+35 is (2x-5)(x-7)

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factor 2x^2-19x+35

factor

2 x^{2} - 19 x + 35

(2 x - 5) (x - 7)

Solution steps

2 x^{2} - 19 x + 35

Break the expression into groups

= (2 x^{2} - 5 x) + (- 14 x + 35)

Factor out

x

from

2 x^{2} - 5 x : x (2 x - 5)

Factor out

- 7

from

- 14 x + 35 : - 7 (2 x - 5)

= x (2 x - 5) - 7 (2 x - 5)

Factor out common term

2 x - 5

= (2 x - 5) (x - 7)

9 x + 2 = 8 x^{2} + 6 x

2 x - 3 > 5 and 3 x - 1 > 11

12 \cdot 18

- 3 x^{2} - 15 x + 72 = 0

7 x^{4} - 343 y^{4}