What is ((x+5)(x-7))/(x+3)<= 0 ?

The solution to ((x+5)(x-7))/(x+3)<= 0 is x<=-5\lor-3<x<= 7

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((x+5)(x-7))/(x+3)<= 0

\frac{( x + 5 ) ( x - 7 )}{x + 3} \leq 0

x \leq - 5 or - 3 < x \leq 7

Interval Notation

(- \infty, - 5] \cup (- 3, 7]

Solution steps

\frac{( x + 5 ) ( x - 7 )}{x + 3} \leq 0

Identify the intervals

x \leq - 5 or - 3 < x \leq 7

lo g_{2} (8) = 3 b + 1

(2 + 10) (2 - 10)

e^{- \frac{π}{2}}

(\frac{a ^{2}}{b})^{7} (\frac{a ^{2} b ^{2}}{c ^{3}})^{4}

lo g_{2} (x) < 0

What is ((x+5)(x-7))/(x+3)<= 0 ?
The solution to ((x+5)(x-7))/(x+3)<= 0 is x<=-5\lor-3<x<= 7