What are the solutions to the equation 6x^2+12x=0 ?

The solutions to the equation 6x^2+12x=0 are x=0,x=-2

Find the zeros of 6x^2+12x=0

The zeros of 6x^2+12x=0 are x=0,x=-2

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6 x^{2} + 12 x = 0

x = 0, x = - 2

Solution steps

6 x^{2} + 12 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 6 \cdot 0}{2 \cdot 6}

1 2^{2} - 4 \cdot 6 \cdot 0 = 12

x_{1, 2} = \frac{- 12 \pm 12}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- 12 + 12}{2 \cdot 6}, x_{2} = \frac{- 12 - 12}{2 \cdot 6}

x = \frac{- 12 + 12}{2 \cdot 6} : 0

x = \frac{- 12 - 12}{2 \cdot 6} : - 2

The solutions to the quadratic equation are:

x = 0, x = - 2

x^{2} - 17 x + 64 = - 6

x^{2} - 1 - 3 > 2

- 5 x + 13 \geq - 7

- 5 \leq 3 x - 2 < 7

9 n^{2} - 23 n + 20 = 3 n^{2}

What are the solutions to the equation 6x^2+12x=0 ?
The solutions to the equation 6x^2+12x=0 are x=0,x=-2
Find the zeros of 6x^2+12x=0
The zeros of 6x^2+12x=0 are x=0,x=-2