What are the solutions to the equation 164=6x^2-4x+2 ?

The solutions to the equation 164=6x^2-4x+2 are x=(1+2sqrt(61))/3 ,x=(1-2sqrt(61))/3

Find the zeros of 164=6x^2-4x+2

The zeros of 164=6x^2-4x+2 are x=(1+2sqrt(61))/3 ,x=(1-2sqrt(61))/3

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164 = 6 x^{2} - 4 x + 2

x = \frac{1 + 2 61}{3}, x = \frac{1 - 2 61}{3}

Solution steps

164 = 6 x^{2} - 4 x + 2

Switch sides

6 x^{2} - 4 x + 2 = 164

Move

164

to the left side

6 x^{2} - 4 x - 162 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 6 ( - 162 )}{2 \cdot 6}

(- 4)^{2} - 4 \cdot 6 (- 162) = 861

x_{1, 2} = \frac{- ( - 4 ) \pm 8 61}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 8 61}{2 \cdot 6}, x_{2} = \frac{- ( - 4 ) - 8 61}{2 \cdot 6}

x = \frac{- ( - 4 ) + 8 61}{2 \cdot 6} : \frac{1 + 2 61}{3}

x = \frac{- ( - 4 ) - 8 61}{2 \cdot 6} : \frac{1 - 2 61}{3}

The solutions to the quadratic equation are:

x = \frac{1 + 2 61}{3}, x = \frac{1 - 2 61}{3}

20.24 = 0.01 v^{2} + 0.7 v

- x^{2} + 3 x - 3 = 0

6 m^{2} - 13 am - 15 a^{2}

15 x - x^{2} = 0

(x + 3)^{2} + 25 = 0

What are the solutions to the equation 164=6x^2-4x+2 ?
The solutions to the equation 164=6x^2-4x+2 are x=(1+2sqrt(61))/3 ,x=(1-2sqrt(61))/3
Find the zeros of 164=6x^2-4x+2
The zeros of 164=6x^2-4x+2 are x=(1+2sqrt(61))/3 ,x=(1-2sqrt(61))/3