What is the answer to |x^2-2x|=1 ?

The answer to |x^2-2x|=1 is x=1-sqrt(2)\lor x=1\lor x=1+sqrt(2)

Solve for x: |x^2-2x|=1

The solution is x=1-sqrt(2)\lor x=1\lor x=1+sqrt(2)

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x^{2} - 2 x = 1

x = 1 - 2 or x = 1 or x = 1 + 2

Decimal Notation

x = - 0.41421 \dots, x = 1, x = 2.41421 \dots

Solution steps

x^{2} - 2 x = 1

Apply absolute rule: If

∣ u ∣ = a, a > 0

then

u = a

u = - a

x^{2} - 2 x = - 1 or x^{2} - 2 x = 1

x^{2} - 2 x = - 1 or x^{2} - 2 x = 1

x = 1 or (x = 1 - 2 or x = 1 + 2)

x = 1 - 2 or x = 1 or x = 1 + 2

\frac{24 + 4 i}{24 - 4 i}

\frac{n ( n + 1 ) ( 2 n + 1 )}{6} + (n + 1)^{2}

40 x^{1} + 8 x^{2} = 800

8 1^{\frac{1}{2}}

(x - 6) (x + 0.7) = 0

What is the answer to |x^2-2x|=1 ?
The answer to |x^2-2x|=1 is x=1-sqrt(2)\lor x=1\lor x=1+sqrt(2)
Solve for x: |x^2-2x|=1
The solution is x=1-sqrt(2)\lor x=1\lor x=1+sqrt(2)