What are the solutions to the equation (x-6)(x+0.7)=0 ?

The solutions to the equation (x-6)(x+0.7)=0 are x=6,x=-0.7

Find the zeros of (x-6)(x+0.7)=0

The zeros of (x-6)(x+0.7)=0 are x=6,x=-0.7

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(x - 6) (x + 0.7) = 0

x = 6, x = - 0.7

Solution steps

(x - 6) (x + 0.7) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 6 = 0 or x + 0.7 = 0

Solve

x - 6 = 0 : x = 6

Solve

x + 0.7 = 0 : x = - 0.7

The solutions to the quadratic equation are:

x = 6, x = - 0.7

∣ 2 x - 2 ∣ > 8

\frac{n ^{2} + 7 n}{4 n ^{2} + 28 n}

\frac{1}{6} < \frac{2 x - 13}{12} < \frac{2}{3}

- 42 = (7.5) t - (4.9) t^{2}

π - x \geq - 5

What are the solutions to the equation (x-6)(x+0.7)=0 ?
The solutions to the equation (x-6)(x+0.7)=0 are x=6,x=-0.7
Find the zeros of (x-6)(x+0.7)=0
The zeros of (x-6)(x+0.7)=0 are x=6,x=-0.7