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What are the solutions to the equation 40x^1+8x^2=800 ?
The solutions to the equation 40x^1+8x^2=800 are x=(5(sqrt(17)-1))/2 ,x=-(5(1+sqrt(17)))/2Find the zeros of 40x^1+8x^2=800
The zeros of 40x^1+8x^2=800 are x=(5(sqrt(17)-1))/2 ,x=-(5(1+sqrt(17)))/2