What are the solutions to the equation -4x^2-7x-2=0 ?

The solutions to the equation -4x^2-7x-2=0 are x=-(7+sqrt(17))/8 ,x=-(7-sqrt(17))/8

Find the zeros of -4x^2-7x-2=0

The zeros of -4x^2-7x-2=0 are x=-(7+sqrt(17))/8 ,x=-(7-sqrt(17))/8

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- 4 x^{2} - 7 x - 2 = 0

x = - \frac{7 + 17}{8}, x = - \frac{7 - 17}{8}

Decimal Notation

x = - 1.39038 \dots, x = - 0.35961 \dots

Solution steps

- 4 x^{2} - 7 x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 ( - 4 ) ( - 2 )}{2 ( - 4 )}

(- 7)^{2} - 4 (- 4) (- 2) = 17

x_{1, 2} = \frac{- ( - 7 ) \pm 17}{2 ( - 4 )}

Separate the solutions

x_{1} = \frac{- ( - 7 ) + 17}{2 ( - 4 )}, x_{2} = \frac{- ( - 7 ) - 17}{2 ( - 4 )}

x = \frac{- ( - 7 ) + 17}{2 ( - 4 )} : - \frac{7 + 17}{8}

x = \frac{- ( - 7 ) - 17}{2 ( - 4 )} : - \frac{7 - 17}{8}

The solutions to the quadratic equation are:

x = - \frac{7 + 17}{8}, x = - \frac{7 - 17}{8}

- 2 + 23 i

4 x^{2} + 8 x + 7 = 0

3 (- \frac{1}{3})^{3} + (- \frac{1}{3})^{2} - 6 (- \frac{1}{3}) - 2

(\frac{10 x ^{3} y ^{2}}{5 x ^{- 3} y ^{4}})^{- 3}

2 x + 4 < 6

What are the solutions to the equation -4x^2-7x-2=0 ?
The solutions to the equation -4x^2-7x-2=0 are x=-(7+sqrt(17))/8 ,x=-(7-sqrt(17))/8
Find the zeros of -4x^2-7x-2=0
The zeros of -4x^2-7x-2=0 are x=-(7+sqrt(17))/8 ,x=-(7-sqrt(17))/8