What are the solutions to the equation r^2-16=0 ?

The solutions to the equation r^2-16=0 are r=4,r=-4

Find the zeros of r^2-16=0

The zeros of r^2-16=0 are r=4,r=-4

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r^{2} - 16 = 0

r = 4, r = - 4

Solution steps

r^{2} - 16 = 0

Move

16

to the right side

r^{2} = 16

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

r = 16, r = - 16

16 = 4

- 16 = - 4

r = 4, r = - 4

(x + 3) (x + 7) = 0

8 - 2 x - x^{2} < 0

- 2 x - 14 \leq 86

\frac{x ^{2} - y ^{2}}{4 x + 4 y} \cdot \frac{x + y}{x - y}

\frac{1}{3} x - \frac{2}{3} = - 18

What are the solutions to the equation r^2-16=0 ?
The solutions to the equation r^2-16=0 are r=4,r=-4
Find the zeros of r^2-16=0
The zeros of r^2-16=0 are r=4,r=-4