What are the solutions to the equation 8z^2-2z-1=0 ?

The solutions to the equation 8z^2-2z-1=0 are z= 1/2 ,z=-1/4

Find the zeros of 8z^2-2z-1=0

The zeros of 8z^2-2z-1=0 are z= 1/2 ,z=-1/4

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8 z^{2} - 2 z - 1 = 0

z = \frac{1}{2}, z = - \frac{1}{4}

Decimal Notation

z = 0.5, z = - 0.25

Solution steps

8 z^{2} - 2 z - 1 = 0

Solve with the quadratic formula

z_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 8 ( - 1 )}{2 \cdot 8}

(- 2)^{2} - 4 \cdot 8 (- 1) = 6

z_{1, 2} = \frac{- ( - 2 ) \pm 6}{2 \cdot 8}

Separate the solutions

z_{1} = \frac{- ( - 2 ) + 6}{2 \cdot 8}, z_{2} = \frac{- ( - 2 ) - 6}{2 \cdot 8}

z = \frac{- ( - 2 ) + 6}{2 \cdot 8} : \frac{1}{2}

z = \frac{- ( - 2 ) - 6}{2 \cdot 8} : - \frac{1}{4}

The solutions to the quadratic equation are:

z = \frac{1}{2}, z = - \frac{1}{4}

\frac{5}{2 \frac{2}{5}}

3 w^{2} = 8 w + 20

(\frac{4}{3}) π^{2.4} \cdot 1 0^{9}

x^{2} + 4 = 4 x

x (x - 1) + x (x - 3) < 48

What are the solutions to the equation 8z^2-2z-1=0 ?
The solutions to the equation 8z^2-2z-1=0 are z= 1/2 ,z=-1/4
Find the zeros of 8z^2-2z-1=0
The zeros of 8z^2-2z-1=0 are z= 1/2 ,z=-1/4