What is the answer to x^2-8x+21=(x-4)^2+3x-16 ?

The answer to x^2-8x+21=(x-4)^2+3x-16 is x=7

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x^2-8x+21=(x-4)^2+3x-16

x^{2} - 8 x + 21 = (x - 4)^{2} + 3 x - 16

x = 7

Solution steps

x^{2} - 8 x + 21 = (x - 4)^{2} + 3 x - 16

Expand

(x - 4)^{2} + 3 x - 16 : x^{2} - 5 x

x^{2} - 8 x + 21 = x^{2} - 5 x

Move

21

to the right side

x^{2} - 8 x = x^{2} - 5 x - 21

Subtract

x^{2} - 5 x

from both sides

x^{2} - 8 x - (x^{2} - 5 x) = x^{2} - 5 x - 21 - (x^{2} - 5 x)

Simplify

- 3 x = - 21

Divide both sides by

- 3

x = 7

(11 - 7 i)^{2}

18 x^{2} + 47 x + 5 = 0

\frac{3}{4} x + \frac{9}{2} \geq \frac{7}{2} + \frac{11}{4}

- x - 1 = 4 x - 11

- 20 x^{10} - 2 x^{5} + 4

What is the answer to x^2-8x+21=(x-4)^2+3x-16 ?
The answer to x^2-8x+21=(x-4)^2+3x-16 is x=7
Solve for x: x^2-8x+21=(x-4)^2+3x-16
The solution is x=7