What are the solutions to the equation -4x^2+8x=9 ?

The solutions to the equation -4x^2+8x=9 are x=1-i(sqrt(5))/2 ,x=1+i(sqrt(5))/2

Find the zeros of -4x^2+8x=9

The zeros of -4x^2+8x=9 are x=1-i(sqrt(5))/2 ,x=1+i(sqrt(5))/2

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- 4 x^{2} + 8 x = 9

x = 1 - i \frac{5}{2}, x = 1 + i \frac{5}{2}

Solution steps

- 4 x^{2} + 8 x = 9

Move

9

to the left side

- 4 x^{2} + 8 x - 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 ( - 4 ) ( - 9 )}{2 ( - 4 )}

Simplify

8^{2} - 4 (- 4) (- 9) : 45 i

x_{1, 2} = \frac{- 8 \pm 4 5 i}{2 ( - 4 )}

Separate the solutions

x_{1} = \frac{- 8 + 4 5 i}{2 ( - 4 )}, x_{2} = \frac{- 8 - 4 5 i}{2 ( - 4 )}

x = \frac{- 8 + 4 5 i}{2 ( - 4 )} : 1 - i \frac{5}{2}

x = \frac{- 8 - 4 5 i}{2 ( - 4 )} : 1 + i \frac{5}{2}

The solutions to the quadratic equation are:

x = 1 - i \frac{5}{2}, x = 1 + i \frac{5}{2}

y^{2} - 6 y + 18 = 0

7 x^{2} + 63 x = 0

(m + 2) (3 m + 10) = 3 (m + 5) + 15

1 - \frac{1}{3}

\frac{1}{4} (1 + 3 (- 0.33))

What are the solutions to the equation -4x^2+8x=9 ?
The solutions to the equation -4x^2+8x=9 are x=1-i(sqrt(5))/2 ,x=1+i(sqrt(5))/2
Find the zeros of -4x^2+8x=9
The zeros of -4x^2+8x=9 are x=1-i(sqrt(5))/2 ,x=1+i(sqrt(5))/2