What are the solutions to the equation 3x^2-8x-7=0 ?

The solutions to the equation 3x^2-8x-7=0 are x=(4+sqrt(37))/3 ,x=(4-sqrt(37))/3

Find the zeros of 3x^2-8x-7=0

The zeros of 3x^2-8x-7=0 are x=(4+sqrt(37))/3 ,x=(4-sqrt(37))/3

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3 x^{2} - 8 x - 7 = 0

x = \frac{4 + 37}{3}, x = \frac{4 - 37}{3}

Decimal Notation

x = 3.36092 \dots, x = - 0.69425 \dots

Solution steps

3 x^{2} - 8 x - 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 3 ( - 7 )}{2 \cdot 3}

(- 8)^{2} - 4 \cdot 3 (- 7) = 237

x_{1, 2} = \frac{- ( - 8 ) \pm 2 37}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 8 ) + 2 37}{2 \cdot 3}, x_{2} = \frac{- ( - 8 ) - 2 37}{2 \cdot 3}

x = \frac{- ( - 8 ) + 2 37}{2 \cdot 3} : \frac{4 + 37}{3}

x = \frac{- ( - 8 ) - 2 37}{2 \cdot 3} : \frac{4 - 37}{3}

The solutions to the quadratic equation are:

x = \frac{4 + 37}{3}, x = \frac{4 - 37}{3}

\frac{( 3 - i )}{1 + i}

- 6 u - 12 + 2 u = 28

x (x - 3) + 3 = 0

\frac{x - 6}{8} \geq \frac{x - 3}{12} + \frac{1}{24}

(\frac{1}{a})^{2}

What are the solutions to the equation 3x^2-8x-7=0 ?
The solutions to the equation 3x^2-8x-7=0 are x=(4+sqrt(37))/3 ,x=(4-sqrt(37))/3
Find the zeros of 3x^2-8x-7=0
The zeros of 3x^2-8x-7=0 are x=(4+sqrt(37))/3 ,x=(4-sqrt(37))/3