What are the solutions to the equation 5x^2+1=37 ?

The solutions to the equation 5x^2+1=37 are x= 6/(sqrt(5)),x=-6/(sqrt(5))

Find the zeros of 5x^2+1=37

The zeros of 5x^2+1=37 are x= 6/(sqrt(5)),x=-6/(sqrt(5))

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5 x^{2} + 1 = 37

x = \frac{6}{5}, x = - \frac{6}{5}

Decimal Notation

x = 2.68328 \dots, x = - 2.68328 \dots

Solution steps

5 x^{2} + 1 = 37

Move

1

to the right side

5 x^{2} = 36

Divide both sides by

5

x^{2} = \frac{36}{5}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{36}{5}, x = - \frac{36}{5}

\frac{36}{5} = \frac{6}{5}

- \frac{36}{5} = - \frac{6}{5}

x = \frac{6}{5}, x = - \frac{6}{5}

x^{7} - x^{3}

(2 + 3) (2 - 3)

x = 64 - x^{2}

- 16 t^{2} + 44 t + 28 = 0

5 x - 6 = 2 x + 12

What are the solutions to the equation 5x^2+1=37 ?
The solutions to the equation 5x^2+1=37 are x= 6/(sqrt(5)),x=-6/(sqrt(5))
Find the zeros of 5x^2+1=37
The zeros of 5x^2+1=37 are x= 6/(sqrt(5)),x=-6/(sqrt(5))