What are the solutions to the equation 1/3 (x-1)^2=12 ?

The solutions to the equation 1/3 (x-1)^2=12 are x=7,x=-5

Find the zeros of 1/3 (x-1)^2=12

The zeros of 1/3 (x-1)^2=12 are x=7,x=-5

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\frac{1}{3} (x - 1)^{2} = 12

x = 7, x = - 5

Solution steps

\frac{1}{3} (x - 1)^{2} = 12

Multiply both sides by

3

(x - 1)^{2} = 36

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 1 = 36 : x = 7

Solve

x - 1 = - 36 : x = - 5

The solutions to the quadratic equation are:

x = 7, x = - 5

(- 7)^{4}

∣ 2 x + 4 ∣ \leq 6

3 x^{2} - 4 x = - 2

∣ x - 1 ∣ > ∣ x + 1 ∣

lo g_{2} (\frac{1}{2}) = x

What are the solutions to the equation 1/3 (x-1)^2=12 ?
The solutions to the equation 1/3 (x-1)^2=12 are x=7,x=-5
Find the zeros of 1/3 (x-1)^2=12
The zeros of 1/3 (x-1)^2=12 are x=7,x=-5