What are the solutions to the equation 3x^2-4x=-2 ?

The solutions to the equation 3x^2-4x=-2 are x= 2/3+i(sqrt(2))/3 ,x= 2/3-i(sqrt(2))/3

Find the zeros of 3x^2-4x=-2

The zeros of 3x^2-4x=-2 are x= 2/3+i(sqrt(2))/3 ,x= 2/3-i(sqrt(2))/3

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3 x^{2} - 4 x = - 2

x = \frac{2}{3} + i \frac{2}{3}, x = \frac{2}{3} - i \frac{2}{3}

Solution steps

3 x^{2} - 4 x = - 2

Move

2

to the left side

3 x^{2} - 4 x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 3 \cdot 2}{2 \cdot 3}

Simplify

(- 4)^{2} - 4 \cdot 3 \cdot 2 : 22 i

x_{1, 2} = \frac{- ( - 4 ) \pm 2 2 i}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 2 2 i}{2 \cdot 3}, x_{2} = \frac{- ( - 4 ) - 2 2 i}{2 \cdot 3}

x = \frac{- ( - 4 ) + 2 2 i}{2 \cdot 3} : \frac{2}{3} + i \frac{2}{3}

x = \frac{- ( - 4 ) - 2 2 i}{2 \cdot 3} : \frac{2}{3} - i \frac{2}{3}

The solutions to the quadratic equation are:

x = \frac{2}{3} + i \frac{2}{3}, x = \frac{2}{3} - i \frac{2}{3}

∣ x - 1 ∣ > ∣ x + 1 ∣

lo g_{2} (\frac{1}{2}) = x

2 x^{2} - 13 x + 4 = 0

x^{2} - 22 x - 23

x^{4} + 50 x^{2} + 625

What are the solutions to the equation 3x^2-4x=-2 ?
The solutions to the equation 3x^2-4x=-2 are x= 2/3+i(sqrt(2))/3 ,x= 2/3-i(sqrt(2))/3
Find the zeros of 3x^2-4x=-2
The zeros of 3x^2-4x=-2 are x= 2/3+i(sqrt(2))/3 ,x= 2/3-i(sqrt(2))/3