What are the solutions to the equation 4x^2-32x+64=0 ?

The solutions to the equation 4x^2-32x+64=0 are x=4

Find the zeros of 4x^2-32x+64=0

The zeros of 4x^2-32x+64=0 are x=4

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4 x^{2} - 32 x + 64 = 0

x = 4

Solution steps

4 x^{2} - 32 x + 64 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 32 ) \pm ( - 32 ) ^{2} - 4 \cdot 4 \cdot 64}{2 \cdot 4}

(- 32)^{2} - 4 \cdot 4 \cdot 64 = 0

x_{1, 2} = \frac{- ( - 32 ) \pm 0}{2 \cdot 4}

x = \frac{- ( - 32 )}{2 \cdot 4}

\frac{- ( - 32 )}{2 \cdot 4} = 4

x = 4

The solution to the quadratic equation is:

x = 4

\frac{3 n ^{2} - 5 n - 2}{2 n - 4}

x^{2} - 10 x + 23 = 0

16 - 83 + 3

125 m^{3} + 27

n^{2} + 6 n - 40

What are the solutions to the equation 4x^2-32x+64=0 ?
The solutions to the equation 4x^2-32x+64=0 are x=4
Find the zeros of 4x^2-32x+64=0
The zeros of 4x^2-32x+64=0 are x=4