What are the solutions to the equation 4x^2-16x=0 ?

The solutions to the equation 4x^2-16x=0 are x=4,x=0

Find the zeros of 4x^2-16x=0

The zeros of 4x^2-16x=0 are x=4,x=0

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4 x^{2} - 16 x = 0

x = 4, x = 0

Solution steps

4 x^{2} - 16 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 16 ) \pm ( - 16 ) ^{2} - 4 \cdot 4 \cdot 0}{2 \cdot 4}

(- 16)^{2} - 4 \cdot 4 \cdot 0 = 16

x_{1, 2} = \frac{- ( - 16 ) \pm 16}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 16 ) + 16}{2 \cdot 4}, x_{2} = \frac{- ( - 16 ) - 16}{2 \cdot 4}

x = \frac{- ( - 16 ) + 16}{2 \cdot 4} : 4

x = \frac{- ( - 16 ) - 16}{2 \cdot 4} : 0

The solutions to the quadratic equation are:

x = 4, x = 0

p^{2} - 4 p - 21 = 0

A = \frac{\frac{3 π}{4} 400}{2}

\frac{\frac{x}{y} - \frac{y}{x}}{\frac{1}{4 x ^{2}} - \frac{1}{4 y ^{2}}}

x^{2} + 8 x + 18 = 0

- \frac{2}{3} + 4

What are the solutions to the equation 4x^2-16x=0 ?
The solutions to the equation 4x^2-16x=0 are x=4,x=0
Find the zeros of 4x^2-16x=0
The zeros of 4x^2-16x=0 are x=4,x=0