What are the solutions to the equation x^2+8x-9=0 ?

The solutions to the equation x^2+8x-9=0 are x=1,x=-9

Find the zeros of x^2+8x-9=0

The zeros of x^2+8x-9=0 are x=1,x=-9

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{2} + 8 x - 9 = 0

x = 1, x = - 9

Solution steps

x^{2} + 8 x - 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 1 \cdot ( - 9 )}{2 \cdot 1}

8^{2} - 4 \cdot 1 \cdot (- 9) = 10

x_{1, 2} = \frac{- 8 \pm 10}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 8 + 10}{2 \cdot 1}, x_{2} = \frac{- 8 - 10}{2 \cdot 1}

x = \frac{- 8 + 10}{2 \cdot 1} : 1

x = \frac{- 8 - 10}{2 \cdot 1} : - 9

The solutions to the quadratic equation are:

x = 1, x = - 9

6 4^{\frac{4}{3}}

2 x^{2} + 18 = 12 x

p^{2} + p - 72

1.1 2^{10}

19 = - 0.1 x^{2} + 70 x

What are the solutions to the equation x^2+8x-9=0 ?
The solutions to the equation x^2+8x-9=0 are x=1,x=-9
Find the zeros of x^2+8x-9=0
The zeros of x^2+8x-9=0 are x=1,x=-9