What are the solutions to the equation 3(4x-1)(4x+3)=48x ?

The solutions to the equation 3(4x-1)(4x+3)=48x are x= 3/4 ,x=-1/4

Find the zeros of 3(4x-1)(4x+3)=48x

The zeros of 3(4x-1)(4x+3)=48x are x= 3/4 ,x=-1/4

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3 (4 x - 1) (4 x + 3) = 48 x

x = \frac{3}{4}, x = - \frac{1}{4}

Decimal Notation

x = 0.75, x = - 0.25

Solution steps

3 (4 x - 1) (4 x + 3) = 48 x

Expand

3 (4 x - 1) (4 x + 3) : 48 x^{2} + 24 x - 9

48 x^{2} + 24 x - 9 = 48 x

Move

48 x

to the left side

48 x^{2} - 24 x - 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 24 ) \pm ( - 24 ) ^{2} - 4 \cdot 48 ( - 9 )}{2 \cdot 48}

(- 24)^{2} - 4 \cdot 48 (- 9) = 48

x_{1, 2} = \frac{- ( - 24 ) \pm 48}{2 \cdot 48}

Separate the solutions

x_{1} = \frac{- ( - 24 ) + 48}{2 \cdot 48}, x_{2} = \frac{- ( - 24 ) - 48}{2 \cdot 48}

x = \frac{- ( - 24 ) + 48}{2 \cdot 48} : \frac{3}{4}

x = \frac{- ( - 24 ) - 48}{2 \cdot 48} : - \frac{1}{4}

The solutions to the quadratic equation are:

x = \frac{3}{4}, x = - \frac{1}{4}

- 2 r^{2} - 12 r + 10 = - 12

x^{2} + 4 x - 5 = 0

4 r^{2} + 44 r + 121 = 0

9 (x + 2)^{2} - 4 = 2

- 12 (x - 8) = 3 (x + 17)

What are the solutions to the equation 3(4x-1)(4x+3)=48x ?
The solutions to the equation 3(4x-1)(4x+3)=48x are x= 3/4 ,x=-1/4
Find the zeros of 3(4x-1)(4x+3)=48x
The zeros of 3(4x-1)(4x+3)=48x are x= 3/4 ,x=-1/4