What is factor 16w^2+8w+1 ?

The solution to factor 16w^2+8w+1 is (4w+1)^2

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factor 16w^2+8w+1

factor

16 w^{2} + 8 w + 1

(4 w + 1)^{2}

Solution steps

16 w^{2} + 8 w + 1

Rewrite in the form of

a^{2} + 2 ab + b^{2} :

16 w^{2} = (4 w)^{2}

1 = 1^{2}

8 w = 2 \cdot 4 w \cdot 1

= (4 w)^{2} + 2 \cdot 4 w \cdot 1 + 1^{2}

Apply Perfect Square Formula:

a^{2} + 2 ab + b^{2} = (a + b)^{2}

(4 w)^{2} + 2 \cdot 4 w \cdot 1 + 1^{2} = (4 w + 1)^{2}

= (4 w + 1)^{2}

\frac{( x + 12 ) ( x - 4 )}{x - 1} \geq 0

64 w^{2} + 96 w + 36 = 0

\frac{a ^{- 4} b ^{4}}{4 a ^{0} b ^{- 4}}

0.01 = (0.000001) (64) (256 - x)

- \frac{70}{3} + 10