What are the solutions to the equation 648+90x-33x^2=0 ?

The solutions to the equation 648+90x-33x^2=0 are x=-36/11 ,x=6

Find the zeros of 648+90x-33x^2=0

The zeros of 648+90x-33x^2=0 are x=-36/11 ,x=6

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648 + 90 x - 33 x^{2} = 0

x = - \frac{36}{11}, x = 6

Decimal Notation

x = - 3.27272 \dots, x = 6

Solution steps

648 + 90 x - 33 x^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

- 33 x^{2} + 90 x + 648 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 90 \pm 9 0 ^{2} - 4 ( - 33 ) \cdot 648}{2 ( - 33 )}

9 0^{2} - 4 (- 33) \cdot 648 = 306

x_{1, 2} = \frac{- 90 \pm 306}{2 ( - 33 )}

Separate the solutions

x_{1} = \frac{- 90 + 306}{2 ( - 33 )}, x_{2} = \frac{- 90 - 306}{2 ( - 33 )}

x = \frac{- 90 + 306}{2 ( - 33 )} : - \frac{36}{11}

x = \frac{- 90 - 306}{2 ( - 33 )} : 6

The solutions to the quadratic equation are:

x = - \frac{36}{11}, x = 6

lo g_{3} (243)

\frac{1}{6} (2 x - 12 x) = 30

3 x^{2} + 36 x = - 42

y \leq 2 and y > - 5

\frac{19 - 4 i}{2 - 5 i} - \frac{3 + 2 i}{i}

What are the solutions to the equation 648+90x-33x^2=0 ?
The solutions to the equation 648+90x-33x^2=0 are x=-36/11 ,x=6
Find the zeros of 648+90x-33x^2=0
The zeros of 648+90x-33x^2=0 are x=-36/11 ,x=6