What are the solutions to the equation 4x^2-8x-45=0 ?

The solutions to the equation 4x^2-8x-45=0 are x= 9/2 ,x=-5/2

Find the zeros of 4x^2-8x-45=0

The zeros of 4x^2-8x-45=0 are x= 9/2 ,x=-5/2

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4 x^{2} - 8 x - 45 = 0

x = \frac{9}{2}, x = - \frac{5}{2}

Decimal Notation

x = 4.5, x = - 2.5

Solution steps

4 x^{2} - 8 x - 45 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 4 ( - 45 )}{2 \cdot 4}

(- 8)^{2} - 4 \cdot 4 (- 45) = 28

x_{1, 2} = \frac{- ( - 8 ) \pm 28}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 8 ) + 28}{2 \cdot 4}, x_{2} = \frac{- ( - 8 ) - 28}{2 \cdot 4}

x = \frac{- ( - 8 ) + 28}{2 \cdot 4} : \frac{9}{2}

x = \frac{- ( - 8 ) - 28}{2 \cdot 4} : - \frac{5}{2}

The solutions to the quadratic equation are:

x = \frac{9}{2}, x = - \frac{5}{2}

\frac{( 3 X - 1 )}{X + 7} < 3

\frac{1}{2} + \frac{1}{4} + \frac{1}{8} + \frac{1}{16} + \frac{1}{32}

- 3 x^{2} + 5 x + 2

3 d^{2} - 11 d + 8 = 6

x^{2} + 3 x - 3 = 0

What are the solutions to the equation 4x^2-8x-45=0 ?
The solutions to the equation 4x^2-8x-45=0 are x= 9/2 ,x=-5/2
Find the zeros of 4x^2-8x-45=0
The zeros of 4x^2-8x-45=0 are x= 9/2 ,x=-5/2