What are the solutions to the equation 3t^2-t=0 ?

The solutions to the equation 3t^2-t=0 are t= 1/3 ,t=0

Find the zeros of 3t^2-t=0

The zeros of 3t^2-t=0 are t= 1/3 ,t=0

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3 t^{2} - t = 0

t = \frac{1}{3}, t = 0

Solution steps

3 t^{2} - t = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 3 \cdot 0}{2 \cdot 3}

(- 1)^{2} - 4 \cdot 3 \cdot 0 = 1

t_{1, 2} = \frac{- ( - 1 ) \pm 1}{2 \cdot 3}

Separate the solutions

t_{1} = \frac{- ( - 1 ) + 1}{2 \cdot 3}, t_{2} = \frac{- ( - 1 ) - 1}{2 \cdot 3}

t = \frac{- ( - 1 ) + 1}{2 \cdot 3} : \frac{1}{3}

t = \frac{- ( - 1 ) - 1}{2 \cdot 3} : 0

The solutions to the quadratic equation are:

t = \frac{1}{3}, t = 0

\frac{12}{4} + 2 (\frac{1}{2}) - 3

13

2 a^{2} + 18 = 0

\frac{1}{4} x^{2} - \frac{1}{2} x = 1

25 x^{2} + 20 x = 6

What are the solutions to the equation 3t^2-t=0 ?
The solutions to the equation 3t^2-t=0 are t= 1/3 ,t=0
Find the zeros of 3t^2-t=0
The zeros of 3t^2-t=0 are t= 1/3 ,t=0