What are the solutions to the equation 5x^2-29x-6=0 ?

The solutions to the equation 5x^2-29x-6=0 are x=6,x=-1/5

Find the zeros of 5x^2-29x-6=0

The zeros of 5x^2-29x-6=0 are x=6,x=-1/5

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5 x^{2} - 29 x - 6 = 0

x = 6, x = - \frac{1}{5}

Solution steps

5 x^{2} - 29 x - 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 29 ) \pm ( - 29 ) ^{2} - 4 \cdot 5 ( - 6 )}{2 \cdot 5}

(- 29)^{2} - 4 \cdot 5 (- 6) = 31

x_{1, 2} = \frac{- ( - 29 ) \pm 31}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- ( - 29 ) + 31}{2 \cdot 5}, x_{2} = \frac{- ( - 29 ) - 31}{2 \cdot 5}

x = \frac{- ( - 29 ) + 31}{2 \cdot 5} : 6

x = \frac{- ( - 29 ) - 31}{2 \cdot 5} : - \frac{1}{5}

The solutions to the quadratic equation are:

x = 6, x = - \frac{1}{5}

- \frac{3}{5} + \frac{7}{2}

4 x^{2} - 2 = 47

x^{2} - 6 x + 6 \leq 0

x = 1 - x^{2}

2 w^{3} - 8 w^{2} - 90 w

What are the solutions to the equation 5x^2-29x-6=0 ?
The solutions to the equation 5x^2-29x-6=0 are x=6,x=-1/5
Find the zeros of 5x^2-29x-6=0
The zeros of 5x^2-29x-6=0 are x=6,x=-1/5