What are the solutions to the equation 0=x^2-5x-6 ?

The solutions to the equation 0=x^2-5x-6 are x=6,x=-1

Find the zeros of 0=x^2-5x-6

The zeros of 0=x^2-5x-6 are x=6,x=-1

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0 = x^{2} - 5 x - 6

x = 6, x = - 1

Solution steps

0 = x^{2} - 5 x - 6

Switch sides

x^{2} - 5 x - 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 1 \cdot ( - 6 )}{2 \cdot 1}

(- 5)^{2} - 4 \cdot 1 \cdot (- 6) = 7

x_{1, 2} = \frac{- ( - 5 ) \pm 7}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 7}{2 \cdot 1}, x_{2} = \frac{- ( - 5 ) - 7}{2 \cdot 1}

x = \frac{- ( - 5 ) + 7}{2 \cdot 1} : 6

x = \frac{- ( - 5 ) - 7}{2 \cdot 1} : - 1

The solutions to the quadratic equation are:

x = 6, x = - 1

- 10 x^{2} + 70 x

- x + 4 x - 1 + 8 - 5 x + 3 - 7 = 2 - 6 x + 1

2 x^{2} + 9 x + 5 \leq 2 - 2 x - 4 x^{2}

\frac{( 2 x + 1 ) ^{2} ( 2 x - 1 ) ^{3}}{( x - 1 ) ^{4}} > 0

\frac{x ^{2}}{y ^{2}}

What are the solutions to the equation 0=x^2-5x-6 ?
The solutions to the equation 0=x^2-5x-6 are x=6,x=-1
Find the zeros of 0=x^2-5x-6
The zeros of 0=x^2-5x-6 are x=6,x=-1