What are the solutions to the equation 5r^2-44r+120=-30+11r ?

The solutions to the equation 5r^2-44r+120=-30+11r are r=6,r=5

Find the zeros of 5r^2-44r+120=-30+11r

The zeros of 5r^2-44r+120=-30+11r are r=6,r=5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

5 r^{2} - 44 r + 120 = - 30 + 11 r

r = 6, r = 5

Solution steps

5 r^{2} - 44 r + 120 = - 30 + 11 r

Move

11 r

to the left side

5 r^{2} - 55 r + 120 = - 30

Move

30

to the left side

5 r^{2} - 55 r + 150 = 0

Solve with the quadratic formula

r_{1, 2} = \frac{- ( - 55 ) \pm ( - 55 ) ^{2} - 4 \cdot 5 \cdot 150}{2 \cdot 5}

(- 55)^{2} - 4 \cdot 5 \cdot 150 = 5

r_{1, 2} = \frac{- ( - 55 ) \pm 5}{2 \cdot 5}

Separate the solutions

r_{1} = \frac{- ( - 55 ) + 5}{2 \cdot 5}, r_{2} = \frac{- ( - 55 ) - 5}{2 \cdot 5}

r = \frac{- ( - 55 ) + 5}{2 \cdot 5} : 6

r = \frac{- ( - 55 ) - 5}{2 \cdot 5} : 5

The solutions to the quadratic equation are:

r = 6, r = 5

- 2 s - 5 = - 11

16 y + 3 y^{2} = 35

4 n^{2} - 4 n - 24 = 0

\frac{4}{3} \cdot \frac{3}{2}

n^{2} + 2 n - 24 = 0

What are the solutions to the equation 5r^2-44r+120=-30+11r ?
The solutions to the equation 5r^2-44r+120=-30+11r are r=6,r=5
Find the zeros of 5r^2-44r+120=-30+11r
The zeros of 5r^2-44r+120=-30+11r are r=6,r=5