What is -x^2+6x>= 0 ?

The solution to -x^2+6x>= 0 is 0<= x<= 6

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-x^2+6x>= 0

- x^{2} + 6 x \geq 0

0 \leq x \leq 6

Interval Notation

[0, 6]

Solution steps

- x^{2} + 6 x \geq 0

Factor

- x^{2} + 6 x : - x (x - 6)

- x (x - 6) \geq 0

Multiply both sides by

- 1

(reverse the inequality)

(- x (x - 6)) (- 1) \leq 0 \cdot (- 1)

Simplify

x (x - 6) \leq 0

Identify the intervals

0 \leq x \leq 6

- 0.05 x^{2} + 10 x - 200 = 0

\frac{6 x ^{4} y ^{7}}{12 x ^{5} y ^{- 8}}

\frac{5}{3} (4)^{2} - \frac{26}{3} (4) + x = - 8

6 x + 58 > 142

7 x - 8 \leq - 15