What is (4^{-1}+2^{-2})/(2^{-3)} ?

The solution to (4^{-1}+2^{-2})/(2^{-3)} is 4

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simplify (4^{-1}+2^{-2})/(2^{-3)}

simplify

\frac{4 ^{- 1} + 2 ^{- 2}}{2 ^{- 3}}

4

Solution steps

\frac{4 ^{- 1} + 2 ^{- 2}}{2 ^{- 3}}

Simplify

4^{- 1} + 2^{- 2} : \frac{1}{2}

= \frac{\frac{1}{2}}{2 ^{- 3}}

Apply the fraction rule:

\frac{\frac{a}{b}}{c} = \frac{a}{b \cdot c}

= \frac{1}{2 \cdot 2 ^{- 3}}

2 \cdot 2^{- 3} = \frac{1}{4}

= \frac{1}{\frac{1}{4}}

Apply the fraction rule:

\frac{1}{\frac{b}{c}} = \frac{c}{b}

= \frac{4}{1}

Divide the numbers:

\frac{4}{1} = 4

= 4

3 x^{6} y^{2} + 81 y^{2}

(5 x)^{\frac{2}{5}}

x^{2} + 12 = 8 x

(3 z - 18)^{2} + 59 = 14

\frac{3 ( x - 5 )}{4} - x = 1 - \frac{x}{6}

What is (4^{-1}+2^{-2})/(2^{-3)} ?
The solution to (4^{-1}+2^{-2})/(2^{-3)} is 4