What are the solutions to the equation 4x^2-1=0 ?

The solutions to the equation 4x^2-1=0 are x= 1/2 ,x=-1/2

Find the zeros of 4x^2-1=0

The zeros of 4x^2-1=0 are x= 1/2 ,x=-1/2

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4 x^{2} - 1 = 0

x = \frac{1}{2}, x = - \frac{1}{2}

Decimal Notation

x = 0.5, x = - 0.5

Solution steps

4 x^{2} - 1 = 0

Move

1

to the right side

4 x^{2} = 1

Divide both sides by

4

x^{2} = \frac{1}{4}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{1}{4}, x = - \frac{1}{4}

\frac{1}{4} = \frac{1}{2}

- \frac{1}{4} = - \frac{1}{2}

x = \frac{1}{2}, x = - \frac{1}{2}

(x - 2)^{2} + 48 = (2 - 3 x)^{2}

(14 - 3) (12 + 7)

- x^{2} + 2 x + 2 = 0

16 x^{2} - 3 = 8 x

\frac{3}{2 i} + i^{5} - (- 3 i + 2)^{2}

What are the solutions to the equation 4x^2-1=0 ?
The solutions to the equation 4x^2-1=0 are x= 1/2 ,x=-1/2
Find the zeros of 4x^2-1=0
The zeros of 4x^2-1=0 are x= 1/2 ,x=-1/2