What are the solutions to the equation -x^2+2x+2=0 ?

The solutions to the equation -x^2+2x+2=0 are x=1-sqrt(3),x=1+sqrt(3)

Find the zeros of -x^2+2x+2=0

The zeros of -x^2+2x+2=0 are x=1-sqrt(3),x=1+sqrt(3)

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- x^{2} + 2 x + 2 = 0

x = 1 - 3, x = 1 + 3

Decimal Notation

x = - 0.73205 \dots, x = 2.73205 \dots

Solution steps

- x^{2} + 2 x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 ( - 1 ) \cdot 2}{2 ( - 1 )}

2^{2} - 4 (- 1) \cdot 2 = 23

x_{1, 2} = \frac{- 2 \pm 2 3}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 2 + 2 3}{2 ( - 1 )}, x_{2} = \frac{- 2 - 2 3}{2 ( - 1 )}

x = \frac{- 2 + 2 3}{2 ( - 1 )} : 1 - 3

x = \frac{- 2 - 2 3}{2 ( - 1 )} : 1 + 3

The solutions to the quadratic equation are:

x = 1 - 3, x = 1 + 3

16 x^{2} - 3 = 8 x

\frac{3}{2 i} + i^{5} - (- 3 i + 2)^{2}

t^{2} + 2 t - 8 = 0

0 = - 25 t^{2} + 200 t + 375

\frac{z}{z - 5} \geq 2 z

What are the solutions to the equation -x^2+2x+2=0 ?
The solutions to the equation -x^2+2x+2=0 are x=1-sqrt(3),x=1+sqrt(3)
Find the zeros of -x^2+2x+2=0
The zeros of -x^2+2x+2=0 are x=1-sqrt(3),x=1+sqrt(3)