What are the solutions to the equation 4x(x+1)=7 ?

The solutions to the equation 4x(x+1)=7 are x=(-1+2sqrt(2))/2 ,x=-(1+2sqrt(2))/2

Find the zeros of 4x(x+1)=7

The zeros of 4x(x+1)=7 are x=(-1+2sqrt(2))/2 ,x=-(1+2sqrt(2))/2

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4 x (x + 1) = 7

x = \frac{- 1 + 2 2}{2}, x = - \frac{1 + 2 2}{2}

Solution steps

4 x (x + 1) = 7

Expand

4 x (x + 1) : 4 x^{2} + 4 x

4 x^{2} + 4 x = 7

Move

7

to the left side

4 x^{2} + 4 x - 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 4 ( - 7 )}{2 \cdot 4}

4^{2} - 4 \cdot 4 (- 7) = 82

x_{1, 2} = \frac{- 4 \pm 8 2}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 4 + 8 2}{2 \cdot 4}, x_{2} = \frac{- 4 - 8 2}{2 \cdot 4}

x = \frac{- 4 + 8 2}{2 \cdot 4} : \frac{- 1 + 2 2}{2}

x = \frac{- 4 - 8 2}{2 \cdot 4} : - \frac{1 + 2 2}{2}

The solutions to the quadratic equation are:

x = \frac{- 1 + 2 2}{2}, x = - \frac{1 + 2 2}{2}

16 v^{2} - 40 v + 25

(\frac{2}{5} m^{2}) (am - \frac{2}{7} t m^{3} - m^{4})

- 1.44

- 4 - (- 4)

\frac{2 ( - 0.51 ) + 1}{\frac{1}{4} - ( - 0.5 1 ^{2} )}

What are the solutions to the equation 4x(x+1)=7 ?
The solutions to the equation 4x(x+1)=7 are x=(-1+2sqrt(2))/2 ,x=-(1+2sqrt(2))/2
Find the zeros of 4x(x+1)=7
The zeros of 4x(x+1)=7 are x=(-1+2sqrt(2))/2 ,x=-(1+2sqrt(2))/2