What are the solutions to the equation 4b^2-7=3b ?

The solutions to the equation 4b^2-7=3b are b= 7/4 ,b=-1

Find the zeros of 4b^2-7=3b

The zeros of 4b^2-7=3b are b= 7/4 ,b=-1

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4 b^{2} - 7 = 3 b

b = \frac{7}{4}, b = - 1

Solution steps

4 b^{2} - 7 = 3 b

Move

3 b

to the left side

4 b^{2} - 7 - 3 b = 0

Write in the standard form

a x^{2} + b x + c = 0

4 b^{2} - 3 b - 7 = 0

Solve with the quadratic formula

b_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 4 ( - 7 )}{2 \cdot 4}

(- 3)^{2} - 4 \cdot 4 (- 7) = 11

b_{1, 2} = \frac{- ( - 3 ) \pm 11}{2 \cdot 4}

Separate the solutions

b_{1} = \frac{- ( - 3 ) + 11}{2 \cdot 4}, b_{2} = \frac{- ( - 3 ) - 11}{2 \cdot 4}

b = \frac{- ( - 3 ) + 11}{2 \cdot 4} : \frac{7}{4}

b = \frac{- ( - 3 ) - 11}{2 \cdot 4} : - 1

The solutions to the quadratic equation are:

b = \frac{7}{4}, b = - 1

7 x + 8 = 4 x + 4

(x + 4)^{2} = 16

2 x = - 15

(- 10 + \frac{20 i}{n})^{2} + (- 10 + \frac{20 i}{n})

9 + 5

What are the solutions to the equation 4b^2-7=3b ?
The solutions to the equation 4b^2-7=3b are b= 7/4 ,b=-1
Find the zeros of 4b^2-7=3b
The zeros of 4b^2-7=3b are b= 7/4 ,b=-1