What are the solutions to the equation (x+4)^2=16 ?

The solutions to the equation (x+4)^2=16 are x=0,x=-8

Find the zeros of (x+4)^2=16

The zeros of (x+4)^2=16 are x=0,x=-8

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(x + 4)^{2} = 16

x = 0, x = - 8

Solution steps

(x + 4)^{2} = 16

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 4 = 16 : x = 0

Solve

x + 4 = - 16 : x = - 8

The solutions to the quadratic equation are:

x = 0, x = - 8

2 x = - 15

(- 10 + \frac{20 i}{n})^{2} + (- 10 + \frac{20 i}{n})

\frac{1}{2} x + \frac{3}{2} (x + 1) - \frac{1}{4} = 5

9 + 5

(\frac{7 a ^{4} b ^{- 4}}{2 a ^{2} b ^{2}})^{- 2}

What are the solutions to the equation (x+4)^2=16 ?
The solutions to the equation (x+4)^2=16 are x=0,x=-8
Find the zeros of (x+4)^2=16
The zeros of (x+4)^2=16 are x=0,x=-8