What are the solutions to the equation (x+5)(x-5)=-9 ?

The solutions to the equation (x+5)(x-5)=-9 are x=4,x=-4

Find the zeros of (x+5)(x-5)=-9

The zeros of (x+5)(x-5)=-9 are x=4,x=-4

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(x + 5) (x - 5) = - 9

x = 4, x = - 4

Solution steps

(x + 5) (x - 5) = - 9

Expand

(x + 5) (x - 5) : x^{2} - 25

x^{2} - 25 = - 9

Move

9

to the left side

x^{2} - 16 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 0 \pm 0 ^{2} - 4 \cdot 1 \cdot ( - 16 )}{2 \cdot 1}

0^{2} - 4 \cdot 1 \cdot (- 16) = 8

x_{1, 2} = \frac{- 0 \pm 8}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 0 + 8}{2 \cdot 1}, x_{2} = \frac{- 0 - 8}{2 \cdot 1}

x = \frac{- 0 + 8}{2 \cdot 1} : 4

x = \frac{- 0 - 8}{2 \cdot 1} : - 4

The solutions to the quadratic equation are:

x = 4, x = - 4

6 b^{2} - 12 b - 90 = 0

- 3 x^{2} - 15 + 5 x = 4

2 x < 10

- \frac{22}{2}

\frac{2}{2 ^{- 4}}

What are the solutions to the equation (x+5)(x-5)=-9 ?
The solutions to the equation (x+5)(x-5)=-9 are x=4,x=-4
Find the zeros of (x+5)(x-5)=-9
The zeros of (x+5)(x-5)=-9 are x=4,x=-4