What are the solutions to the equation 98b^2-50=0 ?

The solutions to the equation 98b^2-50=0 are b= 5/7 ,b=-5/7

Find the zeros of 98b^2-50=0

The zeros of 98b^2-50=0 are b= 5/7 ,b=-5/7

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98 b^{2} - 50 = 0

b = \frac{5}{7}, b = - \frac{5}{7}

Solution steps

98 b^{2} - 50 = 0

Move

50

to the right side

98 b^{2} = 50

Divide both sides by

98

b^{2} = \frac{25}{49}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

b = \frac{25}{49}, b = - \frac{25}{49}

\frac{25}{49} = \frac{5}{7}

- \frac{25}{49} = - \frac{5}{7}

b = \frac{5}{7}, b = - \frac{5}{7}

(\frac{8 x ^{- \frac{1}{2}} y ^{2}}{4 x ^{\frac{2}{3}} y ^{- \frac{1}{4}}})^{3}

12 x^{2} + 17 x = 5

\frac{3 x - 2}{7} = \frac{6 x - 5}{13}

x + 5 < 20

x^{2} + 3 x - 54 < 0

What are the solutions to the equation 98b^2-50=0 ?
The solutions to the equation 98b^2-50=0 are b= 5/7 ,b=-5/7
Find the zeros of 98b^2-50=0
The zeros of 98b^2-50=0 are b= 5/7 ,b=-5/7