What are the solutions to the equation w^2+3w-28=0 ?

The solutions to the equation w^2+3w-28=0 are w=4,w=-7

Find the zeros of w^2+3w-28=0

The zeros of w^2+3w-28=0 are w=4,w=-7

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w^{2} + 3 w - 28 = 0

w = 4, w = - 7

Solution steps

w^{2} + 3 w - 28 = 0

Solve with the quadratic formula

w_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 1 \cdot ( - 28 )}{2 \cdot 1}

3^{2} - 4 \cdot 1 \cdot (- 28) = 11

w_{1, 2} = \frac{- 3 \pm 11}{2 \cdot 1}

Separate the solutions

w_{1} = \frac{- 3 + 11}{2 \cdot 1}, w_{2} = \frac{- 3 - 11}{2 \cdot 1}

w = \frac{- 3 + 11}{2 \cdot 1} : 4

w = \frac{- 3 - 11}{2 \cdot 1} : - 7

The solutions to the quadratic equation are:

w = 4, w = - 7

2 r^{2} - r - 10 = 0

\frac{68}{( 1 - i ) ( 2 - i ) ( 3 - i )}

\frac{48}{2}

3 (3 y - 8) = 30

∣ x + 1 ∣ ∣ x + 2 ∣ = 3

What are the solutions to the equation w^2+3w-28=0 ?
The solutions to the equation w^2+3w-28=0 are w=4,w=-7
Find the zeros of w^2+3w-28=0
The zeros of w^2+3w-28=0 are w=4,w=-7