What are the solutions to the equation 3x^2-14x+6=0 ?

The solutions to the equation 3x^2-14x+6=0 are x=(7+sqrt(31))/3 ,x=(7-sqrt(31))/3

Find the zeros of 3x^2-14x+6=0

The zeros of 3x^2-14x+6=0 are x=(7+sqrt(31))/3 ,x=(7-sqrt(31))/3

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3 x^{2} - 14 x + 6 = 0

x = \frac{7 + 31}{3}, x = \frac{7 - 31}{3}

Decimal Notation

x = 4.18925 \dots, x = 0.47741 \dots

Solution steps

3 x^{2} - 14 x + 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 14 ) \pm ( - 14 ) ^{2} - 4 \cdot 3 \cdot 6}{2 \cdot 3}

(- 14)^{2} - 4 \cdot 3 \cdot 6 = 231

x_{1, 2} = \frac{- ( - 14 ) \pm 2 31}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 14 ) + 2 31}{2 \cdot 3}, x_{2} = \frac{- ( - 14 ) - 2 31}{2 \cdot 3}

x = \frac{- ( - 14 ) + 2 31}{2 \cdot 3} : \frac{7 + 31}{3}

x = \frac{- ( - 14 ) - 2 31}{2 \cdot 3} : \frac{7 - 31}{3}

The solutions to the quadratic equation are:

x = \frac{7 + 31}{3}, x = \frac{7 - 31}{3}

\frac{\frac{1}{x y} - \frac{1}{y ^{2}}}{\frac{1}{x ^{2} y} - \frac{1}{x y ^{2}}}

\frac{3 - 6 i}{4 - 3 i}

- 2 x^{2} - 7 x - 5 = 0

32 a^{2} + 24 b^{2}

x^{2} + \frac{3}{4} = 0

What are the solutions to the equation 3x^2-14x+6=0 ?
The solutions to the equation 3x^2-14x+6=0 are x=(7+sqrt(31))/3 ,x=(7-sqrt(31))/3
Find the zeros of 3x^2-14x+6=0
The zeros of 3x^2-14x+6=0 are x=(7+sqrt(31))/3 ,x=(7-sqrt(31))/3