What are the solutions to the equation 3c^2+4c+8=-6c ?

The solutions to the equation 3c^2+4c+8=-6c are c=-4/3 ,c=-2

Find the zeros of 3c^2+4c+8=-6c

The zeros of 3c^2+4c+8=-6c are c=-4/3 ,c=-2

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3 c^{2} + 4 c + 8 = - 6 c

c = - \frac{4}{3}, c = - 2

Decimal Notation

c = - 1.33333 \dots, c = - 2

Solution steps

3 c^{2} + 4 c + 8 = - 6 c

Move

6 c

to the left side

3 c^{2} + 10 c + 8 = 0

Solve with the quadratic formula

c_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 3 \cdot 8}{2 \cdot 3}

1 0^{2} - 4 \cdot 3 \cdot 8 = 2

c_{1, 2} = \frac{- 10 \pm 2}{2 \cdot 3}

Separate the solutions

c_{1} = \frac{- 10 + 2}{2 \cdot 3}, c_{2} = \frac{- 10 - 2}{2 \cdot 3}

c = \frac{- 10 + 2}{2 \cdot 3} : - \frac{4}{3}

c = \frac{- 10 - 2}{2 \cdot 3} : - 2

The solutions to the quadratic equation are:

c = - \frac{4}{3}, c = - 2

75 \cdot \frac{π}{180}

5 = \frac{u}{12.5}

x^{2} + 4 x - 64 = 4 x

x^{2} + 9 x = 10

x^{8} y^{18}

What are the solutions to the equation 3c^2+4c+8=-6c ?
The solutions to the equation 3c^2+4c+8=-6c are c=-4/3 ,c=-2
Find the zeros of 3c^2+4c+8=-6c
The zeros of 3c^2+4c+8=-6c are c=-4/3 ,c=-2