What are the solutions to the equation 2p^2+7p-30=0 ?

The solutions to the equation 2p^2+7p-30=0 are p= 5/2 ,p=-6

Find the zeros of 2p^2+7p-30=0

The zeros of 2p^2+7p-30=0 are p= 5/2 ,p=-6

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2 p^{2} + 7 p - 30 = 0

p = \frac{5}{2}, p = - 6

Decimal Notation

p = 2.5, p = - 6

Solution steps

2 p^{2} + 7 p - 30 = 0

Solve with the quadratic formula

p_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 2 ( - 30 )}{2 \cdot 2}

7^{2} - 4 \cdot 2 (- 30) = 17

p_{1, 2} = \frac{- 7 \pm 17}{2 \cdot 2}

Separate the solutions

p_{1} = \frac{- 7 + 17}{2 \cdot 2}, p_{2} = \frac{- 7 - 17}{2 \cdot 2}

p = \frac{- 7 + 17}{2 \cdot 2} : \frac{5}{2}

p = \frac{- 7 - 17}{2 \cdot 2} : - 6

The solutions to the quadratic equation are:

p = \frac{5}{2}, p = - 6

\frac{3}{4} x - 2 \geq \frac{5}{3} x + 8

x^{2} + 169 = 0

(- 27)^{\frac{- 2}{3}}

(x^{2} + x - 6) (2 x^{2} + 4 x)

\frac{5}{8} + \frac{1}{2}

What are the solutions to the equation 2p^2+7p-30=0 ?
The solutions to the equation 2p^2+7p-30=0 are p= 5/2 ,p=-6
Find the zeros of 2p^2+7p-30=0
The zeros of 2p^2+7p-30=0 are p= 5/2 ,p=-6