What are the solutions to the equation (2W+7)(W-11)=0 ?

The solutions to the equation (2W+7)(W-11)=0 are W=-7/2 ,W=11

Find the zeros of (2W+7)(W-11)=0

The zeros of (2W+7)(W-11)=0 are W=-7/2 ,W=11

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(2 W + 7) (W - 11) = 0

W = - \frac{7}{2}, W = 11

Decimal Notation

W = - 3.5, W = 11

Solution steps

(2 W + 7) (W - 11) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

2 W + 7 = 0 or W - 11 = 0

Solve

2 W + 7 = 0 : W = - \frac{7}{2}

Solve

W - 11 = 0 : W = 11

The solutions to the quadratic equation are:

W = - \frac{7}{2}, W = 11

r^{3} + 8

5 v^{2} - 21 = 10 v

x^{6} - 8 y^{6}

64 a^{3} + 20 a - 125 b^{3} - 25 b

2 x^{2} - 2 x - 5 = 0

What are the solutions to the equation (2W+7)(W-11)=0 ?
The solutions to the equation (2W+7)(W-11)=0 are W=-7/2 ,W=11
Find the zeros of (2W+7)(W-11)=0
The zeros of (2W+7)(W-11)=0 are W=-7/2 ,W=11