What are the solutions to the equation 1/4 n^2+3=4 ?

The solutions to the equation 1/4 n^2+3=4 are n=2,n=-2

Find the zeros of 1/4 n^2+3=4

The zeros of 1/4 n^2+3=4 are n=2,n=-2

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\frac{1}{4} n^{2} + 3 = 4

n = 2, n = - 2

Solution steps

\frac{1}{4} n^{2} + 3 = 4

Move

3

to the right side

\frac{1}{4} n^{2} = 1

Multiply both sides by

4

n^{2} = 4

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

n = 4, n = - 4

4 = 2

- 4 = - 2

n = 2, n = - 2

7^{2} + b^{2} = 2 5^{2}

4 x + 2 + x^{2} = 0

2 x^{3} - x^{4} \leq 0

lo g_{\frac{1}{4}} (\frac{1}{16})

\frac{a ^{3} - b ^{3}}{( a - b ) ^{2}} + \frac{3 ab}{b - a}

What are the solutions to the equation 1/4 n^2+3=4 ?
The solutions to the equation 1/4 n^2+3=4 are n=2,n=-2
Find the zeros of 1/4 n^2+3=4
The zeros of 1/4 n^2+3=4 are n=2,n=-2